Two blocks A and B of mass m A and m B are connected together by means of a spring and are resting on a horizontal frictionless table. The blocks are then pulled apart so as to stretch the spring and then released. Show that the ratio of their kinetic energies at any instant is in the inverse ratio of their masses.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
By momentum conservation
m A V A = m B V A (i) V B = 
K.E A = 
...(i)
Similiarly K.E B = 
...(iii)
dividing (ii) by (iii) we get.
= 
put V B = 
we get 
= 
.
hence proved
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
Two blocks of masses m and M are moving with speeds v 1 and v 2 (v 1 > v 2 ) in the same direction …
Two masses are connected by a spring as shown in the figure. One of the masses was given velocity v…
Mass A hits B inelastically (e = 0) while moving horizontally with some velocity along the common l…
In the figure shown the change in magnitude of momentum of the block when it comes to its initial p…
Two masses m 1 and m 2 are connected by a spring of spring constant k and are placed on a smooth ho…
Two block of masses m 1 and m 2 are connected with the help of a spring of spring constant k initia…